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<div><a href="../index.html">Home</a> &gt; <a href="index.html">.</a> &gt; qzswitch.m</div>
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<h1>qzswitch
</h1>
<h2><a name="_name"></a>PURPOSE <a href="#_top"><img alt="^" border="0" src="../up.png"></a></h2>
<div class="box"><strong>from Chris Sims web site</strong></div>
<h2><a name="_synopsis"></a>SYNOPSIS <a href="#_top"><img alt="^" border="0" src="../up.png"></a></h2>
<div class="box"><strong>function [A,B,Q,Z] = qzswitch(i,A,B,Q,Z) </strong></div>
<h2><a name="_description"></a>DESCRIPTION <a href="#_top"><img alt="^" border="0" src="../up.png"></a></h2>
<div class="fragment"><pre class="comment"> from Chris Sims web site
http://eco-072399b.princeton.edu/yftp/gensys/mfiles/QZSWITCH.M</pre></div>
<!-- crossreference -->
<h2><a name="_cross"></a>CROSS-REFERENCE INFORMATION <a href="#_top"><img alt="^" border="0" src="../up.png"></a></h2>
This function calls:
<ul style="list-style-image:url(../matlabicon.gif)">
</ul>
This function is called by:
<ul style="list-style-image:url(../matlabicon.gif)">
<li><a href="qzdiv.html" class="code" title="function [A,B,Q,Z] = qzdiv(stake,A,B,Q,Z)">qzdiv</a> from Chris Sims web site</li></ul>
<!-- crossreference -->
<h2><a name="_source"></a>SOURCE CODE <a href="#_top"><img alt="^" border="0" src="../up.png"></a></h2>
<div class="fragment"><pre>0001 <span class="comment">% from Chris Sims web site</span>
0002 <span class="comment">% http://eco-072399b.princeton.edu/yftp/gensys/mfiles/QZSWITCH.M</span>
0003 <span class="comment">%</span>
0004
0005 <a name="_sub0" href="#_subfunctions" class="code">function [A,B,Q,Z] = qzswitch(i,A,B,Q,Z)</a>
0006 <span class="comment">%function [A,B,Q,Z] = qzswitch(i,A,B,Q,Z)</span>
0007 <span class="comment">%</span>
0008 <span class="comment">% Takes U.T. matrices A, B, orthonormal matrices Q,Z, interchanges</span>
0009 <span class="comment">% diagonal elements i and i+1 of both A and B, while maintaining</span>
0010 <span class="comment">% Q'AZ' and Q'BZ' unchanged. If diagonal elements of A and B</span>
0011 <span class="comment">% are zero at matching positions, the returned A will have zeros at both</span>
0012 <span class="comment">% positions on the diagonal. This is natural behavior if this routine is used</span>
0013 <span class="comment">% to drive all zeros on the diagonal of A to the lower right, but in this case</span>
0014 <span class="comment">% the qz transformation is not unique and it is not possible simply to switch</span>
0015 <span class="comment">% the positions of the diagonal elements of both A and B.</span>
0016 realsmall=sqrt(eps)*10;
0017 <span class="comment">%realsmall=1e-3;</span>
0018 a = A(i,i); d = B(i,i); b = A(i,i+1); e = B(i,i+1);
0019 c = A(i+1,i+1); f = B(i+1,i+1);
0020 <span class="comment">% A(i:i+1,i:i+1)=[a b; 0 c];</span>
0021 <span class="comment">% B(i:i+1,i:i+1)=[d e; 0 f];</span>
0022 <span class="keyword">if</span> (abs(c)&lt;realsmall &amp; abs(f)&lt;realsmall)
0023 <span class="keyword">if</span> abs(a)&lt;realsmall
0024 <span class="comment">% l.r. coincident 0's with u.l. of A=0; do nothing</span>
0025 <span class="keyword">return</span>
0026 <span class="keyword">else</span>
0027 <span class="comment">% l.r. coincident zeros; put 0 in u.l. of a</span>
0028 wz=[b; -a];
0029 wz=wz/sqrt(wz'*wz);
0030 wz=[wz [wz(2)';-wz(1)'] ];
0031 xy=eye(2);
0032 <span class="keyword">end</span>
0033 <span class="keyword">elseif</span> (abs(a)&lt;realsmall &amp; abs(d)&lt;realsmall)
0034 <span class="keyword">if</span> abs(c)&lt;realsmall
0035 <span class="comment">% u.l. coincident zeros with l.r. of A=0; do nothing</span>
0036 <span class="keyword">return</span>
0037 <span class="keyword">else</span>
0038 <span class="comment">% u.l. coincident zeros; put 0 in l.r. of A</span>
0039 wz=eye(2);
0040 xy=[c -b];
0041 xy=xy/sqrt(xy*xy');
0042 xy=[[xy(2)' -xy(1)'];xy];
0043 <span class="keyword">end</span>
0044 <span class="keyword">else</span>
0045 <span class="comment">% usual case</span>
0046 wz = [c*e-f*b, (c*d-f*a)'];
0047 xy = [(b*d-e*a)', (c*d-f*a)'];
0048 n = sqrt(wz*wz');
0049 m = sqrt(xy*xy');
0050 <span class="keyword">if</span> m&lt;eps*100
0051 <span class="comment">% all elements of A and B proportional</span>
0052 <span class="keyword">return</span>
0053 <span class="keyword">end</span>
0054 wz = n\wz;
0055 xy = m\xy;
0056 wz = [wz; -wz(2)', wz(1)'];
0057 xy = [xy;-xy(2)', xy(1)'];
0058 <span class="keyword">end</span>
0059 A(i:i+1,:) = xy*A(i:i+1,:);
0060 B(i:i+1,:) = xy*B(i:i+1,:);
0061 A(:,i:i+1) = A(:,i:i+1)*wz;
0062 B(:,i:i+1) = B(:,i:i+1)*wz;
0063 Z(:,i:i+1) = Z(:,i:i+1)*wz;
0064 Q(i:i+1,:) = xy*Q(i:i+1,:);</pre></div>
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