function []=display_problematic_vars_Jacobian(problemrow,problemcol,M_,x,type,caller_string) % []=display_problematic_vars_Jacobian(problemrow,problemcol,M_,ys,caller_string) % print the equation numbers and variables associated with problematic entries % of the Jacobian % % INPUTS % problemrow [vector] rows associated with problematic entries % problemcol [vector] columns associated with problematic entries % M_ [matlab structure] Definition of the model. % x [vector] point at which the Jacobian was evaluated % type [string] 'static' or 'dynamic' depending on the type of % Jacobian % caller_string [string] contains name of calling function for printing % % OUTPUTS % none. % % Copyright (C) 2014-2017 Dynare Team % % This file is part of Dynare. % % Dynare is free software: you can redistribute it and/or modify % it under the terms of the GNU General Public License as published by % the Free Software Foundation, either version 3 of the License, or % (at your option) any later version. % % Dynare is distributed in the hope that it will be useful, % but WITHOUT ANY WARRANTY; without even the implied warranty of % MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the % GNU General Public License for more details. % % You should have received a copy of the GNU General Public License % along with Dynare. If not, see . skipline(); if nargin<6 caller_string=''; end aux_eq_nbr=M_.eq_nbr-M_.orig_eq_nbr; if strcmp(type,'dynamic') for ii=1:length(problemrow) if problemcol(ii)>max(M_.lead_lag_incidence) var_row=2; var_index=problemcol(ii)-max(max(M_.lead_lag_incidence)); else [var_row,var_index]=find(M_.lead_lag_incidence==problemcol(ii)); end if var_row==2 type_string=''; elseif var_row==1 type_string='lag of'; elseif var_row==3 type_string='lead of'; end if problemcol(ii)<=max(max(M_.lead_lag_incidence)) && var_index<=M_.orig_endo_nbr if problemrow(ii)<=aux_eq_nbr eq_nbr=problemrow(ii); fprintf('Derivative of Auxiliary Equation %d with respect to %s Variable %s (initial value of %s: %g) \n',eq_nbr,type_string,deblank(M_.endo_names(var_index,:)),deblank(M_.endo_names(var_index,:)),x(var_index)) else eq_nbr=problemrow(ii)-aux_eq_nbr; fprintf('Derivative of Equation %d with respect to %s Variable %s (initial value of %s: %g) \n',eq_nbr,type_string,deblank(M_.endo_names(var_index,:)),deblank(M_.endo_names(var_index,:)),x(var_index)) end elseif problemcol(ii)<=max(max(M_.lead_lag_incidence)) && var_index>M_.orig_endo_nbr %auxiliary vars if M_.aux_vars(1,problemcol(ii)-M_.orig_endo_nbr).type ==6 %Ramsey Lagrange Multiplier if problemrow(ii)<=aux_eq_nbr eq_nbr=problemrow(ii); fprintf('Derivative of Auxiliary Equation %d with respect to %s of Langrange multiplier of equation %s (initial value: %g) \n',eq_nbr,type_string,M_.aux_vars(1,problemcol(ii)-M_.orig_endo_nbr).eq_nbr,x(problemcol(ii))) else eq_nbr=problemrow(ii)-aux_eq_nbr; fprintf('Derivative of Equation %d with respect to %s of Langrange multiplier of equation %s (initial value: %g) \n',eq_nbr,type_string,M_.aux_vars(1,problemcol(ii)-M_.orig_endo_nbr).eq_nbr,x(problemcol(ii))) end else if problemrow(ii)<=aux_eq_nbr eq_nbr=problemrow(ii); orig_var_index=M_.aux_vars(1,var_index-M_.orig_endo_nbr).orig_index; fprintf('Derivative of Auxiliary Equation %d with respect to %s Variable %s (initial value of %s: %g) \n',eq_nbr,type_string,deblank(M_.endo_names(orig_var_index,:)),deblank(M_.endo_names(orig_var_index,:)),x(orig_var_index)) else eq_nbr=problemrow(ii)-aux_eq_nbr; orig_var_index=M_.aux_vars(1,var_index-M_.orig_endo_nbr).orig_index; fprintf('Derivative of Equation %d with respect to %s Variable %s (initial value of %s: %g) \n',eq_nbr,type_string,deblank(M_.endo_names(orig_var_index,:)),deblank(M_.endo_names(orig_var_index,:)),x(orig_var_index)) end end elseif problemcol(ii)>max(max(M_.lead_lag_incidence)) && var_index<=M_.exo_nbr if problemrow(ii)<=aux_eq_nbr eq_nbr=problemrow(ii); fprintf('Derivative of Auxiliary Equation %d with respect to %s shock %s \n',eq_nbr,type_string,deblank(M_.exo_names(var_index,:))); else eq_nbr=problemrow(ii)-aux_eq_nbr; fprintf('Derivative of Equation %d with respect to %s shock %s \n',eq_nbr,type_string,deblank(M_.exo_names(var_index,:))); end else error('display_problematic_vars_Jacobian:: The error should not happen. Please contact the developers') end end fprintf('\n%s The problem most often occurs, because a variable with\n',caller_string) fprintf('%s exponent smaller than 1 has been initialized to 0. Taking the derivative\n',caller_string) fprintf('%s and evaluating it at the steady state then results in a division by 0.\n',caller_string) fprintf('%s If you are using model-local variables (# operator), check their values as well.\n',caller_string) elseif strcmp(type,'static') for ii=1:length(problemrow) if problemcol(ii)<=M_.orig_endo_nbr if problemrow(ii)<=aux_eq_nbr eq_nbr=problemrow(ii); fprintf('Derivative of Auxiliary Equation %d with respect to Variable %s (initial value of %s: %g) \n',eq_nbr,deblank(M_.endo_names(problemcol(ii),:)),deblank(M_.endo_names(problemcol(ii),:)),x(problemcol(ii))) else eq_nbr=problemrow(ii)-aux_eq_nbr; fprintf('Derivative of Equation %d with respect to Variable %s (initial value of %s: %g) \n',eq_nbr,deblank(M_.endo_names(problemcol(ii),:)),deblank(M_.endo_names(problemcol(ii),:)),x(problemcol(ii))) end else %auxiliary vars if M_.aux_vars(1,problemcol(ii)-M_.orig_endo_nbr).type ==6 %Ramsey Lagrange Multiplier if problemrow(ii)<=aux_eq_nbr eq_nbr=problemrow(ii); fprintf('Derivative of Auxiliary Equation %d with respect to Lagrange multiplier of equation %d (initial value: %g) \n',eq_nbr,M_.aux_vars(1,problemcol(ii)-M_.orig_endo_nbr).eq_nbr,x(problemcol(ii))) else eq_nbr=problemrow(ii)-aux_eq_nbr; fprintf('Derivative of Equation %d with respect to Lagrange multiplier of equation %d (initial value: %g) \n',eq_nbr,M_.aux_vars(1,problemcol(ii)-M_.orig_endo_nbr).eq_nbr,x(problemcol(ii))) end else if problemrow(ii)<=aux_eq_nbr eq_nbr=problemrow(ii); orig_var_index=M_.aux_vars(1,problemcol(ii)-M_.orig_endo_nbr).orig_index; fprintf('Derivative of Auxiliary Equation %d with respect to Variable %s (initial value of %s: %g) \n',eq_nbr,deblank(M_.endo_names(orig_var_index,:)),deblank(M_.endo_names(orig_var_index,:)),x(problemcol(ii))) else eq_nbr=problemrow(ii)-aux_eq_nbr; orig_var_index=M_.aux_vars(1,problemcol(ii)-M_.orig_endo_nbr).orig_index; fprintf('Derivative of Equation %d with respect to Variable %s (initial value of %s: %g) \n',eq_nbr,deblank(M_.endo_names(orig_var_index,:)),deblank(M_.endo_names(orig_var_index,:)),x(problemcol(ii))) end end end end fprintf('\n%s The problem most often occurs, because a variable with\n',caller_string) fprintf('%s exponent smaller than 1 has been initialized to 0. Taking the derivative\n',caller_string) fprintf('%s and evaluating it at the steady state then results in a division by 0.\n',caller_string) fprintf('%s If you are using model-local variables (# operator), check their values as well.\n',caller_string) else error('Unknown Type') end