Added unitary test.
Comparison of the solutions returned by the cyclic reduction and logarithmic reduction algorithm. Note that in the case considered here the logarithmic reduction algorithm is faster.time-shift
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@ -98,4 +98,26 @@ if (nargin == 5 && ~isempty(ch) )
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if (sum(sum(abs(res))) > cvg_tol)
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disp(['the norm residual of the residu ' num2str(res) ' compare to the tolerance criterion ' num2str(cvg_tol)]);
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end
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end
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end
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%@test:1
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%$ addpath ../matlab
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%$
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%$ % Set the dimension of the problem to be solved
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%$ n = 2000;
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%$ % Set the equation to be solved
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%$ A = eye(n);
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%$ B = diag(30*ones(n,1)); B(1,1) = 20; B(end,end) = 20; B = B - diag(10*ones(n-1,1),-1); B = B - diag(10*ones(n-1,1),1);
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%$ C = diag(15*ones(n,1)); C = C - diag(5*ones(n-1,1),-1); C = C - diag(5*ones(n-1,1),1);
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%$
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%$ % Solve the equation with the cycle reduction algorithm
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%$ tic, X1 = cycle_reduction(C,B,A,1e-7); toc
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%$
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%$ % Solve the equation with the logarithmic reduction algorithm
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%$ tic, X2 = logarithmic_reduction(A,B,C,1e-16,100); toc
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%$
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%$ % Check the results.
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%$ t(1) = dyn_assert(X1,X2,1e-12);
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%$
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%$ T = all(t);
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%@eof:1
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