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A model can be solved with (block and/or bytecode) and linear options

time-shift
Ferhat Mihoubi 2011-08-07 10:48:49 +02:00
parent b4b2f21695
commit 95671d8932
1 changed files with 12 additions and 6 deletions
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18
matlab/resol.m
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@ -114,12 +114,18 @@ else
oo_.exo_det_steady_state], M_.params);
end;
else
% linear models
[fvec,jacob] = feval(fh,steady_state,[oo_.exo_steady_state;...
oo_.exo_det_steady_state], M_.params);
if max(abs(fvec)) > 1e-12
steady_state = steady_state-jacob\fvec;
end
if (options_.block == 0 && options_.bytecode == 0)
% linear models
[fvec,jacob] = feval(fh,steady_state,[oo_.exo_steady_state;...
oo_.exo_det_steady_state], M_.params);
if max(abs(fvec)) > 1e-12
steady_state = steady_state-jacob\fvec;
end
else
[steady_state,check1] = dynare_solve_block_or_bytecode(steady_state,...
[oo_.exo_steady_state; ...
oo_.exo_det_steady_state], M_.params);
end;
end
end
end