Correctly distinguish tolerance between steady and perfect foresight
steady uses options_.solve_tolf as a termination criterion, so subsequent checks should do the same. Similarly, solve_tolx was never used.time-shift
parent
4913cfb3f0
commit
607a273bb0
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@ -48,8 +48,10 @@ else
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end
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if strcmp(caller_file_name,'solve_stacked_problem.m')
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tolf = options.dynatol.f;
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tolx = options.dynatol.x;
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else
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tolf = options.solve_tolf;
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tolx = options.solve_tolx;
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end
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if strcmp(caller_file_name,'dyn_ramsey_static.m')
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@ -216,11 +218,11 @@ if options.solve_algo == 0
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end
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elseif options.solve_algo == 1
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[x,info]=solve1(func,x,1:nn,1:nn,jacobian_flag,options.gstep, ...
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tolf,options.solve_tolx, ...
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tolf,tolx, ...
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maxit,options.debug,varargin{:});
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elseif options.solve_algo == 9
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[x,info]=trust_region(func,x,1:nn,1:nn,jacobian_flag,options.gstep, ...
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tolf,options.solve_tolx, ...
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tolf,tolx, ...
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maxit,options.debug,varargin{:});
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elseif options.solve_algo == 2 || options.solve_algo == 4
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@ -252,7 +254,7 @@ elseif options.solve_algo == 2 || options.solve_algo == 4
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end
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[x,info]=solver(func,x,j1(r(i):r(i+1)-1),j2(r(i):r(i+1)-1),jacobian_flag, ...
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options.gstep, ...
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tolf,options.solve_tolx, ...
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tolf,tolx, ...
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maxit,options.debug,varargin{:});
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if info
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return
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@ -261,7 +263,7 @@ elseif options.solve_algo == 2 || options.solve_algo == 4
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fvec = feval(func,x,varargin{:});
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if max(abs(fvec)) > tolf
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[x,info]=solver(func,x,1:nn,1:nn,jacobian_flag, ...
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options.gstep, tolf,options.solve_tolx, ...
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options.gstep, tolf,tolx, ...
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maxit,options.debug,varargin{:});
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end
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elseif options.solve_algo == 3
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@ -111,7 +111,7 @@ if steady_state_checkflag
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info(2) = check; % to be improved
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return
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end
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if max(abs(residuals)) > options.dynatol.f
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if max(abs(residuals)) > options.solve_tolf
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info(1) = 19;
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info(2) = residuals'*residuals;
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return
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@ -88,7 +88,7 @@ else
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if options_.linear == 0
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% nonlinear models
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if max(abs(feval(fh,dr.ys,[oo_.exo_steady_state; ...
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oo_.exo_det_steady_state], M_.params))) > options_.dynatol.f
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oo_.exo_det_steady_state], M_.params))) > options_.solve_tolf
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opt = options_;
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opt.jacobian_flag = false;
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[dr.ys,check1] = dynare_solve(fh,dr.ys,opt,...
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@ -103,7 +103,7 @@ if nargout == 0
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disp('Residuals of the static equations:')
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skipline()
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for i=1:M_.orig_endo_nbr
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if abs(z(i)) < options_.dynatol.f/100
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if abs(z(i)) < options_.solve_tolf/100
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tmp = 0;
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else
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tmp = z(i);
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